Question 8

Last updated at Dec. 21, 2017 by Teachoo

Find the approximate change in the value of 1/x ² , when x changes from x = 2 to x = 2.002

Download Sample Paper of Class 12 here https://www.teachoo.com/cbse/sample-papers/

Transcript

Question 8 Find the approximate change in the value of 1/𝑥^2 , when x changes from x = 2 to x = 2.002 Let y = 1/𝑥^2 We need to find change in value of y when x changes from 2 to 0.002 ∴ ∆x = 2.002 – 2 = 0.002 We need to find ∆y Now, ∆y = 𝑑𝑦/𝑑𝑥 ∆x ∆y = 𝑑(1/𝑥^2 )/𝑑𝑥 ∆x ∆y = 𝑑(𝑥^(−2) )/𝑑𝑥 × 0.002 ∆y = –2 × x–3 × 0.002 Since we go from x = 2 to x = 2.002 We put x = 2 in ∆y ∆y = –2 × 2–3 × 0.002 ∆y = –2 × 1/2^3 × 0.002 ∆y = –2 × 1/2^3 × 2/1000 ∆y = (−1)/2000 ∆y = – 0.0005 ∴ y decreases by 0.0005

CBSE Sample Paper Class 12 - 2017-18

Question 8 You are here

Serial order wise →

Class 12

Sample Papers, Previous Year Papers and Other Questions

CBSE Sample Paper Class 12 - 2017-18

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.

Question 8

Find the approximate change in the value of 1/x 2 , when x changes from x = 2 to x = 2.002

Find the approximate change in the value of 1/x ² , when x changes from x = 2 to x = 2.002