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Find the approximate change in the value of 1/x
^{
2
}
, when x changes from x = 2 to x = 2.002

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Last updated at May 29, 2018 by Teachoo

Download Sample Paper of Class 12 here https://www.teachoo.com/cbse/sample-papers/

Transcript

Question 8 Find the approximate change in the value of 1/๐ฅ^2 , when x changes from x = 2 to x = 2.002 Let y = 1/๐ฅ^2 We need to find change in value of y when x changes from 2 to 0.002 โด โx = 2.002 โ 2 = 0.002 We need to find โy Now, โy = ๐๐ฆ/๐๐ฅ โx โy = ๐(1/๐ฅ^2 )/๐๐ฅ โx โy = ๐(๐ฅ^(โ2) )/๐๐ฅ ร 0.002 โy = โ2 ร xโ3 ร 0.002 Since we go from x = 2 to x = 2.002 We put x = 2 in โy โy = โ2 ร 2โ3 ร 0.002 โy = โ2 ร 1/2^3 ร 0.002 โy = โ2 ร 1/2^3 ร 2/1000 โy = (โ1)/2000 โy = โ 0.0005 โด y decreases by 0.0005

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Class 12

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.