Ex 9.4, 2 - Show homogeneous: y' = x + y / x - Chapter 9 Class 12 - Ex 9.4

part 2 - Ex 9.4, 2 - Ex 9.4 - Serial order wise - Chapter 9 Class 12 Differential Equations
part 3 - Ex 9.4, 2 - Ex 9.4 - Serial order wise - Chapter 9 Class 12 Differential Equations part 4 - Ex 9.4, 2 - Ex 9.4 - Serial order wise - Chapter 9 Class 12 Differential Equations

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Ex 9.4, 2 In each of the Exercise 1 to 10 , show that the given differential equation is homogeneous and solve each of them. š‘¦^′=(š‘„+š‘¦)/š‘„ Step 1: Find š‘‘š‘¦/š‘‘š‘„ š‘‘š‘¦/š‘‘š‘„ = (š‘„ + š‘¦)/š‘„ Step 2: Putting F(x, y) = š‘‘š‘¦/š‘‘š‘„ and find F(šœ†x, šœ†y) So, F(x, y) = (š’™ + š’š)/š’™ F(šœ†x, šœ†y) = (šœ†š‘„ +šœ†š‘¦)/šœ†š‘„ = (šœ†(š‘„ +š‘¦))/šœ†š‘„ = (š‘„ + š‘¦)/š‘„ = F(x, y) = šœ†Ā°F(x, y) Therefore F(x, y) is a homogenous function of degree zero. Hence š‘‘š‘¦/š‘‘š‘„ is a homogenous differential equation Step 3: Solving š‘‘š‘¦/š‘‘š‘„ by putting y = vx Put y = vx. differentiating w.r.t.x š‘‘š‘¦/š‘‘š‘„ = x š‘‘š‘£/š‘‘š‘„+š‘£š‘‘š‘„/š‘‘š‘„ š’…š’š/š’…š’™ = š’™ š’…š’—/š’…š’™ + v Putting value of š‘‘š‘¦/š‘‘š‘„ and y = vx in (1) š‘‘š‘¦/š‘‘š‘„ = (š‘„ + š‘¦)/š‘„ š’™ ( š’…š’—)/š’…š’™ + v = (š’™ + š’—š’™)/š’™ š‘„ ( š‘‘š‘£)/š‘‘š‘„ + v = 1+š‘£ š‘„ (š‘„ š‘‘š‘£)/š‘‘š‘„ = 1+š‘£āˆ’š‘£ š‘„ ( š‘‘š‘£)/š‘‘š‘„ = 1 ( š’…š’—)/š’…š’™ = šŸ/š’™ Integrating both sides ∫1ā–’ć€–š‘‘š‘£=∫1ā–’ć€–š‘‘š‘„/š‘„ 怗 怗 v = log|š’™|+š’„ Putting v = š‘¦/š‘„ š‘¦/š‘„ = log|š‘„| + c y = x log|š’™| + cx

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