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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 9.4, 17 Which of the following is a homogeneous differential equation ? (A) (4𝑥+6𝑦+5)𝑑𝑦−(3𝑦+2𝑥+4)𝑑𝑥=0 (B) (𝑥𝑦)𝑑𝑥−(𝑥^3+𝑦^3 )𝑑𝑦=0 (C) (𝑥^3+2𝑦^2 )𝑑𝑥+2𝑥𝑦 𝑑𝑦=0 (D) 𝑦^2 𝑑𝑥+(𝑥^2+𝑥𝑦−𝑦^2 )𝑑𝑦=0Let us check each equation one by one Checking Option (A) Differential equation can be written as (4𝑥+6𝑦+5)𝑑𝑦−(3𝑦+2𝑥+4)𝑑𝑥 𝑑𝑦/𝑑𝑥 = ((3𝑦 + 2𝑥 + 4))/((4𝑥 + 6𝑦 + 5)) Let F(x, y) = 𝑑𝑦/𝑑𝑥 = ((3𝑦 + 2𝑥 + 4))/((4𝑥 + 6𝑦 + 5)) Finding F(𝝀x, 𝝀y) F(𝜆x, 𝜆y) = (2𝜆𝑥 + 3𝜆𝑦 + 4)/(4𝜆𝑥 + 6𝜆𝑦 + 5) ≠ 𝜆° F(x, y) ∴ The given equation is not homogenous Checking Option (B) (B) Differential equation can be written as (𝑥𝑦)𝑑𝑥−(𝑥^3+𝑦^3 )𝑑𝑦 = 0 𝑑𝑦/𝑑𝑥 = 𝑥𝑦/(𝑥^3 + 𝑦^3 ) Let F(x, y) = 𝑑𝑦/𝑑𝑥 = 𝑥𝑦/(𝑥^3 + 𝑦^3 ) Finding F(𝝀x, 𝝀y) F(𝜆x, 𝜆y) = (𝜆𝑥 𝜆𝑦)/(𝜆^3 𝑥^3 + 𝜆^3 𝑦^3 ) = (𝜆^2 𝑥𝑦)/(𝜆^3 [𝑥^3 + 𝑦^3 ] ) = 𝑥𝑦/𝜆(𝑥^3+𝑦^3 ) ≠ 𝜆° F(x, y) ∴ The given equation is not homogenous Checking Option (C) (𝑥^3+2𝑦^2 )𝑑𝑥+2𝑥𝑦 𝑑𝑦=0 (x3 + 2y2) dx = −2xy dy 𝑑𝑦/𝑑𝑥 = (−(𝑥^3 + 2𝑦^2))/2𝑥𝑦 Let F(x, y) = 𝑑𝑦/𝑑𝑥 = (−(𝑥^3 + 2𝑦^2))/2𝑥𝑦 Finding F(𝝀x, 𝝀y) F(𝜆x, 𝜆y) = (−(𝜆^3 𝑥^3 + 2𝜆^2 𝑦^2))/2𝜆𝑥𝜆𝑦 = (−〖6𝑥〗^3 + 2𝑦^2)/2𝑥𝑦 ≠ 𝜆° F(x, y) ∴ The given equation is not homogenous Checking Option (D) y2 dx + (x2 − xy − y2) dy = 0 y2 dx = (x2 − xy − y2)dy 𝑑𝑦/𝑑𝑥 = 𝑦^2/(𝑥^2 − 𝑥𝑦 − 𝑦2) Let F(x, y) = 𝑑𝑦/𝑑𝑥 = 𝑦^2/(𝑥^2 − 𝑥𝑦 − 𝑦2) Finding F(𝝀x, 𝝀y) F(𝜆x, 𝜆y) = 〖−𝜆^(2 ) 𝑦〗^2/(𝜆^(2 ) (𝑥^2 − 𝑥𝑦 − 𝑦2)) = 𝑦^2/(𝑥^2 − 𝑥𝑦 − 𝑦2) = 𝜆°F (x, y) F (x, y) is 𝑎 homogenous function of degree zero. ∴ Given equation is a homogenous differential equation. Hence, (D) is the correct answer.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.