# Ex 9.5, 8 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Nov. 14, 2019 by

Last updated at Nov. 14, 2019 by

Transcript

Ex 9.5, 8 show that the given differential equation is homogeneous and solve each of them. + =0 Step 1: Find = y x sin Step 2. Put = F (x, y) and find F( x, y) F(x, y) = sin F( x, y) = sin = sin = F(x, y) = ( , ) F (x, y) is a homogenous function of degree 0 . So the differential equation is homogenous Step 3 : Let y = vx Solving = - sin Putting y = vx Diff w.r.t.x = x + v = x + v Putting value of = 2 + 2 2 + and y = vx in (1) = y x sin v + = sin v + = sin v = v sin v v = sin = sin = Integrating both sides = = log cot = log + log log cot + log = log log ( cot ) = log x (cosec v cot v) = C x 1 sin cos sin = C x (1 cos ) sin = C x(1 cos v) = C sin v Putting value of v = x = C sin

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.