Question 11 - Finding equation of tangent/normal when slope and curve are given - Chapter 6 Class 12 Application of Derivatives
Last updated at April 16, 2024 by Teachoo
Finding equation of tangent/normal when slope and curve are given
Question 10 Deleted for CBSE Board 2024 Exams
Question 3 Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams You are here
Question 15 Important Deleted for CBSE Board 2024 Exams
Question 25 Deleted for CBSE Board 2024 Exams
Question 21 Important Deleted for CBSE Board 2024 Exams
Question 14 Important Deleted for CBSE Board 2024 Exams
Finding equation of tangent/normal when slope and curve are given
Last updated at April 16, 2024 by Teachoo
Question 11 Find the equation of all lines having slope 2 which are tangents to the curve 𝑦=1/(𝑥 − 3) , 𝑥≠3.The Equation of Given Curve is : 𝑦=1/(𝑥 − 3) We know that Slope of tangent is 𝑑𝑦/𝑑𝑥 𝑑𝑦/𝑑𝑥=𝑑(1/(𝑥 − 3))/𝑑𝑥 𝑑𝑦/𝑑𝑥=𝑑/𝑑𝑥 (𝑥−3)^(−1) 𝑑𝑦/𝑑𝑥=(−1) (𝑥−3)^(−1−1) . 𝑑(𝑥 − 3)/𝑑𝑥 𝑑𝑦/𝑑𝑥=−(𝑥−3)^(−2) 𝑑𝑦/𝑑𝑥=(−1)/(𝑥 − 3)^2 Given that slope = 2 Hence, 𝑑𝑦/𝑑𝑥 = 2 ∴ (−1)/(𝑥 − 3)^2 =2 −1=2(𝑥−3)^2 〖2(𝑥−3)〗^2=−1 (𝑥−3)^2=(−1)/( 2) We know that Square of any number is always positive So, (𝑥−3)^2>0 ∴ (𝑥−3)^2=(−1)/( 2) not possible Thus, No tangent to the Curve has Slope 2