You are here
Question 11 - Finding equation of tangent/normal when slope and curve are given - Chapter 6 Class 12 Application of Derivatives
Last updated at August 8, 2026 by Teachoo
Finding equation of tangent/normal when slope and curve are given
Chapter 6 Class 12 Application of Derivatives
Concept wise
- Finding rate of change
- To show increasing/decreasing in whole domain
- To show increasing/decreasing in intervals
- Find intervals of increasing/decreasing
- Finding slope of tangent/normal
- Finding point when tangent is parallel/ perpendicular
- Finding equation of tangent/normal when point and curve is given
-
Finding equation of tangent/normal when slope and curve are given
- Finding approximate value of numbers
- Finding approximate value of function
- Finding approximate value- Statement questions
- Finding minimum and maximum values from graph
- Local maxima and minima
- Minima/ maxima (statement questions) - Number questions
- Minima/ maxima (statement questions) - Geometry questions
- Absolute minima/maxima
Take a fresh quiz. Then take another.
Every attempt is a new AI-adaptive Teachoo quiz with 2 questions, selected from your answers, mistakes, and progress.
Transcript
Question 11 Find the equation of all lines having slope 2 which are tangents to the curve š¦=1/(š„ ā 3) , š„ā 3.The Equation of Given Curve is : š¦=1/(š„ ā 3) We know that Slope of tangent is šš¦/šš„ šš¦/šš„=š(1/(š„ ā 3))/šš„ šš¦/šš„=š/šš„ (š„ā3)^(ā1) šš¦/šš„=(ā1) (š„ā3)^(ā1ā1) . š(š„ ā 3)/šš„ šš¦/šš„=ā(š„ā3)^(ā2) šš¦/šš„=(ā1)/(š„ ā 3)^2 Given that slope = 2 Hence, šš¦/šš„ = 2 ā“ (ā1)/(š„ ā 3)^2 =2 ā1=2(š„ā3)^2 ć2(š„ā3)ć^2=ā1 (š„ā3)^2=(ā1)/( 2) We know that Square of any number is always positive So, (š„ā3)^2>0 ā“ (š„ā3)^2=(ā1)/( 2) not possible Thus, No tangent to the Curve has Slope 2
