Ex 6.2, 10 - Prove logarithmic function is strictly increasing

Ex 6.2,10 - Chapter 6 Class 12 Application of Derivatives - Part 2

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Ex 6.2, 10 Prove that the logarithmic function is strictly increasing on (0, โˆž).f(๐‘ฅ) = log (๐‘ฅ) We need to prove f(๐‘ฅ) in increasing on ๐‘ฅ โˆˆ (0 , โˆž) i.e. we need to show fโ€™(๐’™) > 0 for x โˆˆ (๐ŸŽ , โˆž) Now, f(๐‘ฅ) = log ๐‘ฅ fโ€™(๐‘ฅ) = 1/๐‘ฅ When ๐’™ > 0 (1 )/๐‘ฅ > 0 fโ€™(๐‘ฅ) > 0 โˆด f(๐‘ฅ) is an increasing function for ๐‘ฅ > 0 Hence, f(๐‘ฅ) is an increasing function for (0, โˆž). Hence proved

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