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Ex 1.3
Ex 1.3, 2 Deleted for CBSE Board 2023 Exams
Ex 1.3, 3 (i) Important Deleted for CBSE Board 2023 Exams
Ex 1.3, 3 (ii) Deleted for CBSE Board 2023 Exams
Ex 1.3 , 4 Deleted for CBSE Board 2023 Exams
Ex 1.3, 5 (i) Deleted for CBSE Board 2023 Exams
Ex 1.3, 5 (ii) Important Deleted for CBSE Board 2023 Exams
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Ex 1.3 , 8 Important Deleted for CBSE Board 2023 Exams
Ex 1.3 , 9 Important Deleted for CBSE Board 2023 Exams
Ex 1.3, 10 Important Deleted for CBSE Board 2023 Exams
Ex 1.3, 11 Deleted for CBSE Board 2023 Exams
Ex 1.3, 12 Deleted for CBSE Board 2023 Exams
Ex 1.3, 13 (MCQ) Important Deleted for CBSE Board 2023 Exams
Ex 1.3, 14 (MCQ) Important Deleted for CBSE Board 2023 Exams You are here
Last updated at March 16, 2023 by Teachoo
Ex 1.3, 14 Let f : R – {(−4)/3} → R be a function defined as f (x) = 4𝑥/(3𝑥 + 4) The inverse of f is map g: Range f → R – {(−4)/3}given by (A) g (y) = 3𝑦/(3−4𝑦) (B) g (y) = 4𝑦/(4−3𝑦) (C) g (y) = 4𝑦/(3−4𝑦) (D) g (y) = 3𝑦/(4−3𝑦) f(x) = 4𝑥/(3𝑥 + 4) Calculating inverse Take f(x) = y Hence, equation becomes y = 4𝑥/(3𝑥 + 4) y(3x + 4) = 4x 3xy + 4y = 4x 3xy – 4x = – 4y x(3y – 4) = – 4y x = (−4𝑦)/(3𝑦 − 4) x = (−4𝑦)/(−1(−3𝑦 + 4)) x = 4𝑦/((4 − 3𝑦)) So, inverse of f = 4𝑦/((4 − 3𝑦)) ∴ g(y) = 4𝑦/((4 − 3𝑦)) Hence, B is the correct answer