


Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Inverse of a function
Ex 1.3, 2 Deleted for CBSE Board 2024 Exams You are here
Ex 1.3, 3 (i) Important Deleted for CBSE Board 2024 Exams
Ex 1.3, 3 (ii) Deleted for CBSE Board 2024 Exams
Ex 1.3 , 4 Deleted for CBSE Board 2024 Exams
Ex 1.3, 5 (i) Deleted for CBSE Board 2024 Exams
Ex 1.3, 5 (ii) Important Deleted for CBSE Board 2024 Exams
Ex 1.3, 5 (iii) Important Deleted for CBSE Board 2024 Exams
Ex 1.3 , 6 Deleted for CBSE Board 2024 Exams
Ex 1.3 , 7 Deleted for CBSE Board 2024 Exams
Ex 1.3 , 8 Important Deleted for CBSE Board 2024 Exams
Ex 1.3 , 9 Important Deleted for CBSE Board 2024 Exams
Ex 1.3, 10 Important Deleted for CBSE Board 2024 Exams
Ex 1.3, 11 Deleted for CBSE Board 2024 Exams
Ex 1.3, 12 Deleted for CBSE Board 2024 Exams
Ex 1.3, 13 (MCQ) Important Deleted for CBSE Board 2024 Exams
Ex 1.3, 14 (MCQ) Important Deleted for CBSE Board 2024 Exams
Inverse of a function
Last updated at May 29, 2023 by Teachoo
Ex 1.3, 2 (Introduction) Let f, g and h be functions from R to R. Show that (f + g)oh = foh + goh (f.g)oh = (foh).(goh) Let f(x) = x, g(x) = sin x , h(x) = log x We will show (f + g) oh = foh + goh Let f(x) = x, g(x) = sin x , h(x) = log x To prove: We will show (f .g) oh = foh . goh (f .g) oh = foh . goh Ex 1.3, 2 Let f, g and h be functions from R to R. Show that (f + g)oh = foh + goh & (f.g) oh = (foh).(goh) Proving (f + g) oh = foh + goh L.H.S (f + g)oh = (f + g) (h(x)) = f (h(x)) + g (h(x)) = foh + goh = R.H.S Hence, (f + g) oh = foh + goh Proving (f .g) oh = foh . goh L.H.S (f . g)oh = (f . g) (h(x)) = f (h(x)) . g (h(x)) = foh . goh = R.H.S Hence, (f . g) oh = (foh) . (goh)