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Ex 1.3

Ex 1.3, 1
Deleted for CBSE Board 2023 Exams

Ex 1.3, 2 Deleted for CBSE Board 2023 Exams You are here

Ex 1.3, 3 (i) Important Deleted for CBSE Board 2023 Exams

Ex 1.3, 3 (ii) Deleted for CBSE Board 2023 Exams

Ex 1.3 , 4 Deleted for CBSE Board 2023 Exams

Ex 1.3, 5 (i) Deleted for CBSE Board 2023 Exams

Ex 1.3, 5 (ii) Important Deleted for CBSE Board 2023 Exams

Ex 1.3, 5 (iii) Important Deleted for CBSE Board 2023 Exams

Ex 1.3 , 6 Deleted for CBSE Board 2023 Exams

Ex 1.3 , 7 Deleted for CBSE Board 2023 Exams

Ex 1.3 , 8 Important Deleted for CBSE Board 2023 Exams

Ex 1.3 , 9 Important Deleted for CBSE Board 2023 Exams

Ex 1.3, 10 Important Deleted for CBSE Board 2023 Exams

Ex 1.3, 11 Deleted for CBSE Board 2023 Exams

Ex 1.3, 12 Deleted for CBSE Board 2023 Exams

Ex 1.3, 13 (MCQ) Important Deleted for CBSE Board 2023 Exams

Ex 1.3, 14 (MCQ) Important Deleted for CBSE Board 2023 Exams

Chapter 1 Class 12 Relation and Functions

Serial order wise

Last updated at May 29, 2018 by Teachoo

Ex 1.3, 2 (Introduction) Let f, g and h be functions from R to R. Show that (f + g)oh = foh + goh (f.g)oh = (foh).(goh) Let f(x) = x, g(x) = sin x , h(x) = log x We will show (f + g) oh = foh + goh Let f(x) = x, g(x) = sin x , h(x) = log x To prove: We will show (f .g) oh = foh . goh (f .g) oh = foh . goh Ex 1.3, 2 Let f, g and h be functions from R to R. Show that (f + g)oh = foh + goh & (f.g) oh = (foh).(goh) Proving (f + g) oh = foh + goh L.H.S (f + g)oh = (f + g) (h(x)) = f (h(x)) + g (h(x)) = foh + goh = R.H.S Hence, (f + g) oh = foh + goh Proving (f .g) oh = foh . goh L.H.S (f . g)oh = (f . g) (h(x)) = f (h(x)) . g (h(x)) = foh . goh = R.H.S Hence, (f . g) oh = (foh) . (goh)