# Example 41

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 41 If y = 1 , show that (1 2) 2 2 = 0 . We have = 1 Differentiating . . . = 1 = 1 1 2 = Now, = 1 2 1 2 Again Differentiating . . . = 1 2 1 2 2 2 = 1 2 1 2 1 2 1 . 1 2 2 2 = 1 2 1 2 3 2 . (1) ( 2 ) 2 2 = 1 2 1 2 3 2 . 0 2 2 2 = 1 2 1 2 3 2 . 2 = Now, we need to prove 1 2 2 2 . = 0 Solving LHS 1 2 2 2 . = 1 2 . 1 2 3 2 1 2 1 2 = 1 2 1+ 3 2 1 2 1 2 = 1 2 1 2 1 2 1 2 = 0 = RHS Hence proved .

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Class 12

Important Question for exams Class 12

- Chapter 1 Class 12 Relation and Functions
- Chapter 2 Class 12 Inverse Trigonometric Functions
- Chapter 3 Class 12 Matrices
- Chapter 4 Class 12 Determinants
- Chapter 5 Class 12 Continuity and Differentiability
- Chapter 6 Class 12 Application of Derivatives
- Chapter 7 Class 12 Integrals
- Chapter 8 Class 12 Application of Integrals
- Chapter 9 Class 12 Differential Equations
- Chapter 10 Class 12 Vector Algebra
- Chapter 11 Class 12 Three Dimensional Geometry
- Chapter 12 Class 12 Linear Programming
- Chapter 13 Class 12 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.