Ex 5.4, 3 - Ex 5.4

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Ex 5.4, 3 Differentiate š‘¤.š‘Ÿ.š‘”. š‘„ in, 怖 š‘’ć€—^(š‘„^3 ) Let š‘¦ =怖 š‘’ć€—^(š‘„^3 ) " " Differentiating both sides š‘¤.š‘Ÿ.š‘”.š‘„ š‘‘(š‘¦)/š‘‘š‘„ = š‘‘(怖 š‘’ć€—^(š‘„^3 ) )/š‘‘š‘„ š‘‘š‘¦/š‘‘š‘„ = 怖 š‘’ć€—^(š‘„^3 ) . š‘‘(š‘„^3 )/š‘‘š‘„ š‘‘š‘¦/š‘‘š‘„ = 怖 š‘’ć€—^(š‘„^3 ) . 3š‘„^2 š’…š’š/š’…š’™ = šŸ‘š’™^šŸ 怖 š’†ć€—^(š’™^šŸ‘ )

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