Ex 5.4, 3 - Ex 5.4

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Transcript

Ex 5.4, 3 Differentiate ๐‘ค.๐‘Ÿ.๐‘ก. ๐‘ฅ in, ใ€– ๐‘’ใ€—^(๐‘ฅ^3 ) Let ๐‘ฆ =ใ€– ๐‘’ใ€—^(๐‘ฅ^3 ) " " Differentiating both sides ๐‘ค.๐‘Ÿ.๐‘ก.๐‘ฅ ๐‘‘(๐‘ฆ)/๐‘‘๐‘ฅ = ๐‘‘(ใ€– ๐‘’ใ€—^(๐‘ฅ^3 ) )/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = ใ€– ๐‘’ใ€—^(๐‘ฅ^3 ) . ๐‘‘(๐‘ฅ^3 )/๐‘‘๐‘ฅ ๐‘‘๐‘ฆ/๐‘‘๐‘ฅ = ใ€– ๐‘’ใ€—^(๐‘ฅ^3 ) . 3๐‘ฅ^2 ๐’…๐’š/๐’…๐’™ = ๐Ÿ‘๐’™^๐Ÿ ใ€– ๐’†ใ€—^(๐’™^๐Ÿ‘ )

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