Ex 5.4, 6 - Chapter 5 Class 12 Continuity and Differentiability

Last updated at August 7, 2026 by

Ex 5.4, 6 - Ex 5.4

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Ex 5.4, 6 Differentiate š‘¤.š‘Ÿ.š‘”. š‘„ in , š‘’^š‘„+ š‘’^(š‘„^2 ) + š‘’^(š‘„^3 )+ š‘’^(š‘„^4 ) + š‘’^(š‘„^5 )Let š‘¦ = š‘’^š‘„+ š‘’^(š‘„^2 ) +... + š‘’^(š‘„^5 ) y = š‘’^š‘„+ š‘’^(š‘„^2 ) + š‘’^(š‘„^3 )+ š‘’^(š‘„^4 ) + š‘’^(š‘„^5 ) Differentiating both sides š‘¤.š‘Ÿ.š‘”.š‘„ š‘‘(š‘¦)/š‘‘š‘„ = š‘‘(š‘’^š‘„ " + " š‘’^(š‘„^2 ) " + " š‘’^(š‘„^3 ) " + " š‘’^(š‘„^4 ) " + " š‘’^(š‘„^5 ) )/š‘‘š‘„ = (š‘‘(š‘’^š‘„ ) )/š‘‘š‘„ + š‘‘(š‘’^(š‘„^2 ) )/š‘‘š‘„ + š‘‘(š‘’^(š‘„^3 ) )/š‘‘š‘„ + š‘‘(š‘’^(š‘„^4 ) )/š‘‘š‘„ + š‘‘(š‘’^(š‘„^5 ) )/š‘‘š‘„ = š‘’^š‘„ + š‘’^(š‘„^2 ). š‘‘(š‘„^2 )/š‘‘š‘„ + š‘’^(š‘„^3 ). š‘‘(š‘„^3 )/š‘‘š‘„ + š‘’^(š‘„^4 ). š‘‘(š‘„^4 )/š‘‘š‘„ + š‘’^(š‘„^5 ). š‘‘(š‘„^5 )/š‘‘š‘„ = š’†^š’™ + 2xš’†^(š’™^šŸ ) + šŸ‘š’™^šŸ š’†^(š’™^šŸ‘ ) + šŸ’š’™^šŸ‘ š’†^(š’™^šŸ’ ) + 怖šŸ“š’™ć€—^(šŸ’ ) š’†^(š’™^šŸ“ )

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