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Misc 6 - Chapter 4 Class 12 Determinants

Last updated at June 11, 2023 by

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Misc 6 Evaluate |■8(1&x&y@1&x+y&y@1&x&x+y)| |■8(1&x&y@1&x+y&y@1&x&x+y)| Applying R1→ R1 – R2 = |■8(𝟏−𝟏&x−x−y&y@1&x+y&y@1&𝑥&x+y)| = |■8(𝟎&−y&y@1&x+y&y@1&𝑥&x+y)| Applying R2→ R2 – R3 = |■8(0&−y&0@𝟏−𝟏&x+y−x&y−x−y@1&x&x+y)| = |■8(0&−y&0@𝟎&y&−x@1&𝑥&x+y)| Expanding determinant along C1 = 0 |■8(𝑦&−𝑥@𝑥&𝑥+𝑦)| – 0 |■8(−𝑦&𝑦@𝑥&𝑥+𝑦)| + 1 |■8(−𝑦&0@𝑦&−𝑥)| = 0 – 0 + 1 |■8(−𝑦&0@𝑦&−𝑥)| = (0 – 0 + 1(xy)) = xy

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.