Misc 5 - Solve |x+a x x x x+a x x x x+a| = 0 - Class 12 - Miscellaneous

Misc 5 - Chapter 4 Class 12 Determinants - Part 2
Misc 5 - Chapter 4 Class 12 Determinants - Part 3

Remove Ads Take short quiz All Quiz and Worksheets
Teachoo · Class 12 Explore Class 12

Transcript

Question 3 Solve the equations 𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷯﷯ = 0, a ≠ 0 Solving ∆ = 𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷯﷯ Applying R1 → R1 + R2 + R3 = 𝑥+𝑎+𝑥+𝑥﷮𝑥+𝑥+𝑎+𝑥﷮𝑥+𝑥+𝑥+𝑎﷮𝑥﷮𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷯﷯ = 𝟑𝒙+𝒂﷮𝟑𝒙+𝒂﷮𝟑𝒙+𝒂﷮𝑥﷮𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷯﷯ Taking (3x + a) common from R1 = (3x + a) 1﷮1﷮1﷮𝑥﷮𝑥+𝑎﷮𝑥﷮𝑥﷮𝑥﷮𝑥+𝑎﷯﷯ Applying C2 → C2 – C1 = (3x + a) 1﷮𝟏−𝟏﷮1﷮𝑥﷮𝑥+𝑎−𝑥﷮𝑥﷮𝑥﷮𝑥−𝑥﷮𝑥+𝑎﷯﷯ = (3x+ a) 1﷮𝟎﷮1﷮𝑥﷮𝑎﷮𝑥﷮𝑥﷮0﷮𝑥+𝑎﷯﷯ Applying C3 →C3 – C1 = (3x + a) 1﷮0﷮𝟏−𝟏﷮𝑥﷮𝑎﷮𝑥−𝑥﷮𝑥﷮0﷮𝑥+𝑎−𝑥﷯﷯ = (3x + a) 1﷮0﷮𝟎﷮𝑥﷮𝑎﷮0﷮𝑥﷮0﷮𝑎﷯﷯ = (3x+ a) 1 𝑎﷮0﷮0﷮𝑎﷯﷯−0 𝑥﷮0﷮𝑥﷮0﷯﷯+0 𝑥﷮𝑎﷮𝑥﷮0﷯﷯﷯ = (3x+ a) 1 𝑎﷮0﷮0﷮𝑎﷯﷯−0+0﷯ = (3x+ a) (1(a2 – 0) – 0 + 0) = (3x+ a) (a2) ∴ ∆ = (3x+ a) (a2) Given ∆ = 0 ∴ (3x + a) a2 = 0

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.