


Ex 4.2
Ex 4.2, 2 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 3 Deleted for CBSE Board 2022 Exams
Ex 4.2, 4 Deleted for CBSE Board 2022 Exams
Ex 4.2, 5 Important Deleted for CBSE Board 2022 Exams You are here
Ex 4.2, 6 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 7 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 8 (i) Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 8 (ii) Deleted for CBSE Board 2022 Exams
Ex 4.2, 9 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 10 (i) Deleted for CBSE Board 2022 Exams
Ex 4.2, 10 (ii) Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 11 (i) Deleted for CBSE Board 2022 Exams
Ex 4.2, 11 (ii) Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 12 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 13 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 14 Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 15 (MCQ) Important Deleted for CBSE Board 2022 Exams
Ex 4.2, 16 (MCQ) Deleted for CBSE Board 2022 Exams
Last updated at Jan. 22, 2020 by Teachoo
Ex 4.2, 5 Using the property of determinants and without expanding, prove that: |■8(b+c&q+r&y+z@c+a&r+p&z+x@a+b&p+q&x+y)| = 2 |■8(a&p&x@b&q&y@c&r&z)| Solving L.H.S |■8(b+c&q+r&y+z@c+a&r+p&z+x@a+b&p+q&x+y)| Applying R3 → R3 + R2 + R1 = |■8(𝑏+𝑐&𝑞+𝑟&𝑦+𝑧@𝑐+𝑎&𝑟+𝑝&𝑧+𝑥@𝑎+𝑏+𝑐+𝑎+𝑏+𝑐&𝑝+𝑞+𝑟+𝑞+𝑞+𝑟&𝑥+𝑦+𝑧+𝑥+𝑦+𝑧)| = |■8(b+𝑐&𝑞+𝑟&𝑦+𝑧@c+a&r+𝑝&z+x@𝟐(a+b+c)&𝟐(𝑝+𝑞+𝑟)&𝟐(x+𝑦+𝑧))| Taking 2 common from R3 = 2 |■8(b+𝑐&𝑞+𝑟&𝑦+𝑧@c+a&r+𝑝&z+x@(a+b+c)&(𝑝+𝑞+𝑟)&(x+𝑦+𝑧))| Applying R1 → R1 – R3 = 2 |■8(b+𝑐 −(a+b+c)&𝑞+𝑟 −(𝑝+𝑞+𝑟)&𝑦+𝑧 −(x+𝑦+𝑧)@c+a&r+𝑝&z+x@(a+b+c)&(𝑝+𝑞+𝑟)&(x+𝑦+𝑧))| = 2 |■8(b+𝑐−𝑎−𝑏−𝑐&𝑞+𝑟−𝑝−𝑞−𝑟&𝑦+𝑧−𝑥−𝑦−𝑧@c+a&r+𝑝&z+x@a+b+c&𝑝+𝑞+𝑟&x+𝑦+𝑧)| = 2 |■8(−𝑎&−𝑝&−𝑥@c+a&r+𝑝&z+x@a+b+c&𝑝+𝑞+𝑟&x+𝑦+𝑧)| Applying R2 → R2 – R3 = 2 |■8(−𝑎&−𝑝&−𝑥@c+a−a−b−c&r+𝑝−𝑝−𝑞−𝑟&z+x−x−y−z@a+b+c&𝑝+𝑞+𝑟&x+𝑦+𝑧)| = 2 |■8(−𝑎&−𝑝&−𝑥@−b&−𝑞&−y@a+b+c&𝑝+𝑞+𝑟&x+𝑦+𝑧)| Applying R3 → R3 + R1 + R2 = 2 |■8(−𝑎&−𝑝&−𝑥@−b&−𝑞&−y@a+b+c−𝑎−𝑏&𝑝+𝑞+𝑟−𝑝−𝑞&x+𝑦+𝑧−𝑥−𝑦)| = 2 |■8(−𝑎&−𝑝&−𝑥@−b&−𝑞&−y@𝑐&𝑟&𝑧)| Taking –1 Common from R1 & R3 = 2 ( –1) ( –1)|■8(𝑎&𝑝&𝑥@b&𝑞&y@𝑐&𝑟&𝑧)| = 2 |■8(𝑎&𝑝&𝑥@b&𝑞&y@𝑐&𝑟&𝑧)| = R.H.S Hence Proved