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Ex 4.2
Ex 4.2, 2 Important Deleted for CBSE Board 2023 Exams You are here
Ex 4.2, 3 Deleted for CBSE Board 2023 Exams
Ex 4.2, 4 Deleted for CBSE Board 2023 Exams
Ex 4.2, 5 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 6 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 7 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 8 (i) Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 8 (ii) Deleted for CBSE Board 2023 Exams
Ex 4.2, 9 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 10 (i) Deleted for CBSE Board 2023 Exams
Ex 4.2, 10 (ii) Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 11 (i) Deleted for CBSE Board 2023 Exams
Ex 4.2, 11 (ii) Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 12 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 13 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 14 Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 15 (MCQ) Important Deleted for CBSE Board 2023 Exams
Ex 4.2, 16 (MCQ) Deleted for CBSE Board 2023 Exams
Last updated at March 16, 2023 by Teachoo
Ex 4.2, 2 Using the property of determinants and without expanding, prove that: |■8(a−b&b−c&c−𝑎@b−c&c−a&a−[email protected]−a&a−b&b−c)| = 0 |■8(a−b&b−c&c−𝑎@b−c&c−a&a−[email protected]−a&a−b&b−c)| Making first row 0 by Applying R1 →R1 + R2 + R3 = |■8(a−b+b−c+c−a&b−c+c−a+a−b&c−a+a−b+b−[email protected]−c&c−a&a−[email protected]−a&a−b&b−c)| = |■8(0&0&[email protected]−c&c−a&a−[email protected]−a&a−b&b−c)| = 0 |■8(c−a&a−[email protected]−b&b−c)| – 0 |■8(b−c&a−[email protected]−a&b−c)| + 0 |■8(b−c&c−[email protected]−a&a−b)| = 0 – 0 + 0 = 0 = R.H.S Thus, L.H.S = R.H.S Hence proved