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Example 12 - Chapter 4 Class 9 - Exploring Algebraic Identities (Ganita Manjari I)
Last updated at May 15, 2026 by Teachoo
Factorisation by Splitting the Middle term
Class 9
Chapter 4 Class 9 - Exploring Algebraic Identities (Ganita Manjari I)
- Consecutive Square Numbers
- Visualising Algebraic Identities
- Exercise Set 4.1
- Factorisation of Algebraic Expressions Using Identities
- Exercise Set 4.2
- More Identities
- Exercise Set 4.3
- Rewriting a2 - b2 Identity
- Factorisation Using Algebra Tiles
-
Factorisation by Splitting the Middle term
- Exercise Set 4.4
- Finding New Algebraic Identities
- Simplifying Rational Expressions
- Exercise Set 4.5
- Word Problems
- End-of-Chapter Exercises
Transcript
Example 12 Factorise 𝑥^2−5𝑥+6 x2 – 5x + 6 = x2 – 2x – 3x + 6 = x(x – 2) – 3(x – 2) = (x – 2) (x – 3) Splitting the middle term method We need to find two numbers whose Sum = –5 Product = 1 × 6 = 6 Since sum is negative but product is positive. Thus, both numbers are negative
