Question 9 - End-of-Chapter Exercises - Chapter 2 Class 9 - Introduction to Linear Polynomials (Ganita Manjari

Transcript

Question 9 The work done by a body on the application of a constant force is the product of the constant force and the distance travelled by the body in the direction of the force. Express this in the form of a linear equation in two variables (work w and distance d), and draw its graph by taking the constant force as 3 units. What is the work done when the distance travelled is 2 units? Verify it by plotting it on the graph. Let Work done = w Distance travelled by body = d Also, given that Constant force = 3 units Thus, our linear equation is Work done = Constant force × Distance w = 3d We can take Work done as y Distance as x And draw the graph Work done = Constant force × Distance w = 3d We can take Work done as y Distance as x And draw the graph Putting d = 0 w = 3 × 0 w = 0 So, x = 0, y = 0 lie on the line i.e. (0, 0) lies on the line Putting d = 1 w = 3 × 1 w = 3 So, x = 1, y = 3 lie on the line i.e. (1, 3) lies on the line We plot all the points in the graph and join the points w = 3d Also, we are asked What is the work done when the distance travelled is 2 units? Our equation is Work done = 3 × Distance travelled Putting Distance travelled = 2 Work done = 3 × 2 = 6 units