Baudhāyana’s Theorem on Right-angled triangles
Last updated at February 20, 2026 by Teachoo
Transcript
Question 4 - Figure it out (Page 47) Let a, b and c denote the length of the sides of a right triangle, with c being the length of the hypotenuse. Find the missing sidelength in each of the following cases: (i) a = 5, b = 7Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 52 + 72 c2 = 25 + 49 c2 = 64 c = √64 c = √(8^2 ) c = 8 Thus, Hypotenuse = c is 8 Question 4 - Figure it out (Page 47) Let a, b and c denote the length of the sides of a right triangle, with c being the length of the hypotenuse. Find the missing sidelength in each of the following cases: (ii) a = 8, b = 12Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 82 + 122 c2 = 64 + 144 c2 = 208 c = √𝟐𝟎𝟖 Thus, Hypotenuse = c is √𝟐𝟎𝟖 (approx. 14.42). Question 4 - Figure it out (Page 47) Let a, b and c denote the length of the sides of a right triangle, with c being the length of the hypotenuse. Find the missing sidelength in each of the following cases: (iii) a = 9, c = 15Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 152 = 92 + b2 225 = 81 + b2 225 – 81= b2 b2 = 225 – 81 b2 = 144 b = √144 b = √(12^2 ) b = 12 Thus, length of third side = b is 12 Question 4 - Figure it out (Page 47) Let a, b and c denote the length of the sides of a right triangle, with c being the length of the hypotenuse. Find the missing sidelength in each of the following cases: (iv) a = 7, b = 12Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 72 + 122 c2 = 49 + 144 c2 = 193 c = √𝟏𝟗𝟑 Thus, Hypotenuse = c is √𝟏𝟗𝟑 (approx. 13.89). Question 4 - Figure it out (Page 47) Let a, b and c denote the length of the sides of a right triangle, with c being the length of the hypotenuse. Find the missing sidelength in each of the following cases: (v) a = 1.5, b = 3.5Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = (1.5) 2 + (3.5) 2 c2 = (15/10)^2+(35/10)^2 c2 = 225/100+1225/100 c2 = (𝟐𝟐𝟓 + 𝟏𝟐𝟐𝟓)/𝟏𝟎𝟎 c2 = 1450/100 c2 = 145/10 c2 = 14.5 c = √(𝟏𝟒.𝟓) Thus, Hypotenuse = c is √(𝟏𝟒.𝟓) (approx. 3.81).