The Baudhayana-Pythagoras Theorem - Chapter 2 Class 8 (Ganita Part 2)

Master The Baudhayana-Pythagoras Theorem - Chapter 2 Class 8 (Ganita Part 2) with comprehensive NCERT Solutions, Practice Questions, MCQs, Sample Papers, Case Based Questions, and Video lessons.

NCERT Solutions

The Baudhayana-Pythagoras Theorem - Chapter 2 Class 8 (Ganita Part 2) – NCERT Solutions

Each question below opens its complete step-by-step Teachoo solution.

Figure it out - Page 39, 40

3 questions

Question 1

Earlier, we saw a method to create a square with double the area of a given square paper. There is another method to do this in which two identical square papers are cut in the following way. Can you arrange these pieces to create a square with double the area of either square?Alright, let’s do this
We follow these steps
Look at your four triangles (labeled 1, 2, 3, and 4). They are all identical isosceles right triangles.
Each triangle has one right angle (a perfect 90-degree corner) and one longest side (the hypotenuse).
Imagine sliding all four of those triangles together so that their right-angle corners all meet perfectly in the center, pointing inward.
When you do this, the longest sides (the hypotenuses) are now facing outward. Because all four hypotenuses are the same length, they form the straight outside edges of a brand new, tilted square!

View solution

Question 2

(i) The length of the two equal sides of an isosceles right triangle is given. Find the length of the hypotenuse. Find bounds on the length of the hypotenuse such that they have at least one digit after the decimal point. (i) 3 Our figure looks like

View solution

Question 3

The hypotenuse of an isosceles right triangle is 10. What are its other two sidelengths? [Hint: Find the area of the square composed of two such right triangles.]Let Side of isosceles triangle be a

View solution

Figure it out - Page 50

3 questions

Question 1

Find 5 more Baudhāyana triples using this idea.We use our equation
〖(𝒏−𝟏)〗^𝟐 + (𝟐𝒏−𝟏)=𝒏^𝟐
Here,
2n – 1 is an odd square number

View solution

Question 2

Does this method yield non-primitive Baudhāyana triples? [Hint: Observe that among the triples generated, one of the smaller sidelengths is one less than the hypotenuse.]No, it never yields non-primitive triples.

View solution

Question 3

Are there primitive triples that cannot be obtained through this method? If yes, give examples.Yes, there are.
The method on this page strictly produces triples where the hypotenuse is exactly 𝟏 unit larger than one of the legs (because they are 𝑛 and 𝑛−1 ).

View solution

Figure it out - Page 52, 53, 54

9 questions

Question 1

Find the diagonal of a square with sidelength 5 cm.Here, Diagonal is BD

View solution

Question 2

Find the missing sidelengths in the following right triangles:Let’s do one-by-one
Figure 1

View solution

Question 3

Find the sidelength of a rhombus whose diagonals are of length 24 units and 70 units.A rhombus is a quadrilateral with all sides equal
And, its diaognals bisect each other at right angles

View solution

Question 4

Is the hypotenuse the longest side of a right triangle? Justify your answer.Yes!
By Baudhāyana-Pythagoras Theorem
c2 = a2 + b2

View solution

Question 5

True or False — Every Baudhāyana triple is either a primitive triple or a scaled version of a primitive triple.True.
A "primitive" triple is one where the three numbers share no common factors (like 3, 4, 5).
Every other Baudhāyana triple in existence is just a scaled-up version of a primitive one (like multiplying 3, 4, 5 by two to get 6, 8, 10).

View solution

Question 6

Give 5 examples of rectangles whose sidelengths and diagonals are all integers.Let’s draw a rectangle

View solution

Question 7

Construct a square whose area is equal to the difference of the areas of squares of sidelengths 5 units and 7 units.Let Side of required square = a
Thus,
Area of required square = a2

View solution

Question 8

(i) Using the dots of a grid as the vertices, can you create a square that has an area of (a) 2 sq. units, (b) 3 sq. units, (c) 4 sq.units, and (d) 5 sq. unit?When you draw a square on a dot grid (where every dot is at a whole-number coordinate), you might draw it perfectly straight, or you might draw it tilted.
Think about the Baudhāyana-Pythagoras theorem:
𝒂^𝟐+𝒃^𝟐=𝒄^𝟐.

View solution

Question 9

Find the area of an equilateral triangle with sidelength 6 units. [Hint: Show that an altitude bisects the opposite side. Use this to find the height.]Let’s draw the figure
Find the height (altitude)
Let us draw perpendicular from point A
Thus, AD is the height

View solution

Why Learn This With Teachoo?

The Baudhayana–Pythagoras Theorem, also written as the Baudhāyana–Pythagoras Theorem, is Chapter 2 of NCERT Class 8 Ganita Prakash Part 2. It develops the right-triangle relationship through square areas, doubling and halving squares, the diagonal of an isosceles right triangle, √2, Pythagorean triples and practical applications. The chapter also places the result in Indian mathematical history. Teachoo explains the geometry and calculations step by step.

From squares to right triangles

Doubling a square asks how to construct or determine a square with twice the original area. If a square has side a, its area is a². The diagonal divides it into two congruent right triangles and becomes the side of a larger related square. For a unit square, the diagonal has length √2 because its square equals 1² + 1².

Halving a square reverses the area relationship. These investigations make square roots geometric: √2 is not only a symbol or decimal but the exact length of the diagonal of a unit square. The chapter examines its decimal representation and recognises that it does not terminate in a simple finite form.

The theorem and Pythagorean triples

For a right-angled triangle with perpendicular sides a and b and hypotenuse c, the Baudhāyana–Pythagoras theorem states a² + b² = c². The hypotenuse is always opposite the right angle and is the triangle’s longest side.

Combining two squares provides a visual interpretation: the areas of squares on the two legs together equal the area of the square on the hypotenuse. The theorem can find a missing side or test whether a triangle is right-angled.

Pythagorean triples are integer sets satisfying a² + b² = c², such as 3, 4 and 5. The chapter discusses a long-standing open problem in the history of equations and provides further applications involving distances, diagonals and constructions.

Topics covered on Teachoo

Teachoo includes:

  • doubling and halving a square;

  • hypotenuse of an isosceles right triangle;

  • decimal representation of √2;

  • formula for the isosceles right-triangle hypotenuse;

  • combining two squares;

  • Baudhāyana’s theorem for right-angled triangles;

  • Pythagorean triples;

  • a long-standing open problem;

  • further applications; and

  • Figure it out solutions for pages 39–40, 50 and 52–54.

Learning outcomes

Students should be able to connect side lengths with areas of squares, calculate a missing side in a right triangle and determine whether three lengths form a right triangle. They should explain why a unit-square diagonal is √2, recognise Pythagorean triples and apply the theorem to distances and geometric designs. They should identify the hypotenuse before substituting values.

Why is this chapter important?

The theorem is central to geometry, construction, coordinate distance, navigation, engineering and physics. The area interpretation gives a reason for the formula and prepares students for irrational numbers. The historical framing also shows that major mathematical ideas often developed across cultures and names.

How Teachoo helps

Teachoo divides the chapter from square-area explorations to theorem applications. Draw the right angle clearly, label the hypotenuse and write the squared relation before inserting numbers. If finding a leg, subtract its known square from the hypotenuse square; if finding the hypotenuse, add the leg squares.

Estimate the final length before taking a root. It must be positive, and the hypotenuse must exceed either leg. Compare your diagram and equation with Teachoo’s solution after attempting the question independently.

Common mistakes to avoid

The theorem applies only to right-angled triangles. Do not identify the hypotenuse as whichever side is drawn slanting; it is the side opposite the right angle. Square the lengths before adding or subtracting, and take the square root only after finding the missing square.

Quick revision checklist

Draw and label several right triangles in different orientations, always marking the hypotenuse from the right angle. Find a missing hypotenuse, find a missing leg and test whether three given lengths form a right triangle. Construct or describe the diagonal of a unit square and connect it with √2. Finish by recognising and scaling common Pythagorean triples and checking whether the resulting lengths remain a valid triple.

Preparing for application questions

Real problems may describe a ladder, rectangular diagonal, shortest distance, construction or square plot without explicitly mentioning the theorem. Sketch the situation and locate a right angle before forming the equation. State what each side represents and retain exact roots when an exact answer is requested. If a decimal length is needed, approximate only at the final step and check that the answer is geometrically possible.

Deeper reasoning and concept connections

A student has understood The Baudhayana–Pythagoras Theorem (Ganita Prakash Part 2) only when the idea can be moved between words, diagrams, examples and mathematical notation. Start with a concrete example, identify what changes and what remains fixed, represent the relationship clearly and then state the rule. This movement between representations is important because school and competency questions often present a familiar idea in an unfamiliar form.

The chapter should also be connected to earlier and later mathematics. Definitions supply the language, worked examples reveal the method, and mixed questions test whether the method can be selected without a hint. Instead of memorising the appearance of a solved question, ask what information triggered the method, which condition made it valid and how the answer could be checked. That makes learning transferable to later chapters rather than limited to one exercise.

How to solve unfamiliar and competency-based questions

Read the complete problem before calculating. Underline the quantities, conditions and command word—find, compare, construct, justify, estimate or prove. Rephrase the task in one sentence and choose a representation such as a table, labelled figure, number line, expression or graph. Solve in small steps, keeping units and labels visible.

For an application question, the final line must answer the situation, not only display a number. For an assertion–reason question, test the assertion and reason separately before deciding whether one explains the other. For an MCQ, eliminate options using definitions, signs, size estimates or boundary cases before performing long calculations. If the answer is visual, check it against the stated scale or construction conditions rather than the appearance of the drawing.

What complete mastery looks like

For The Baudhayana–Pythagoras Theorem (Ganita Prakash Part 2), a student should be able to define the central ideas in simple language, recognise them in different representations, solve routine questions accurately and explain the method used. They should also be able to correct a flawed solution, create an example satisfying given conditions and combine two ideas from the chapter in one problem. A reliable mastery test is to solve one direct question, one application question and one reasoning question without looking at notes, then explain all three aloud or in writing.

Keep a compact error log with four labels: concept, interpretation, calculation and presentation. Reattempt each error after a gap instead of rereading the answer immediately. Improvement comes from correcting the decision that caused the mistake, not from repeating questions whose method is already known.

Additional frequently asked questions

What should a student know before starting The Baudhayana–Pythagoras Theorem (Ganita Prakash Part 2)?

Revise the definitions, number operations, diagrams or notation used at the beginning of the chapter. The prerequisite list should be short: if an earlier skill blocks progress, repair that skill with two or three focused questions and return to the chapter.

How can a student check an answer in The Baudhayana–Pythagoras Theorem (Ganita Prakash Part 2)?

Use an independent check whenever possible: substitute the result, reverse the operation, estimate its size, compare it with the figure, test a simpler case or solve using another representation. A check should examine the mathematical condition, not merely repeat the same arithmetic.

How many questions are enough for strong preparation?

There is no fixed number. Stop counting questions and track coverage: every concept, every standard method, at least one mixed problem, one competency-based problem and every previously incorrect type should be solved independently. Ten varied, analysed questions are more valuable than fifty copied solutions.

How should Teachoo solutions be used without becoming dependent on them?

Attempt the question first and mark the exact step where progress stops. Read only enough of the solution to repair that step, close it and restart the question. Finally, solve a similar problem without help. This turns a solution into feedback rather than a substitute for thinking.

Frequently asked questions

What does the Baudhāyana–Pythagoras theorem state?

In a right triangle, the square of the hypotenuse equals the sum of the squares of the other two sides.

Why is the diagonal of a unit square √2?

It is the hypotenuse of a right triangle with legs 1 and 1, so its square is 1² + 1² = 2.

What is a Pythagorean triple?

It is a set of positive integers a, b and c satisfying a² + b² = c².

Begin with the geometry, not the formula. Once the correct right triangle is identified, the calculation becomes direct.