[Maths] Find the missing sidelengths in the following right triangles - Figure it out - Page 52, 53, 54

part 2 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
part 3 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 4 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 5 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 6 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT) part 7 - Question 2 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 2 Find the missing sidelengths in the following right triangles:Let’s do one-by-one Figure 1 Here, a = 7, b = 9, c = ? By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 72 + 92 c2 = 49 + 81 c2 = 130 c = √𝟏𝟑𝟎 Figure 2 Here, a = 4, b = 10, c = ? By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 42 + 102 c2 = 16 + 100 c2 = 116 c = √𝟏𝟏𝟔 Figure 3 Here, a = ?, b = 40, c = 41 By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 412 = a2 + 402 1681 = a2 + 1600 1681 – 1600 = a2 81 = a2 a2 = 81 a = √81 a = 𝟗 Figure 4 Here, a = ?, b = 10, c = √𝟐𝟎𝟎 By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 (√𝟐𝟎𝟎)^𝟐 = a2 + 102 200 = a2 + 100 200 – 100 = a2 100 = a2 a2 = 100 a = √100 a = 10 Figure 5 Here, a = 10, b = √𝟏𝟓𝟎, c = ? By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 102 + (√𝟏𝟓𝟎)^𝟐 c2 = 100 + 150 c2 = 250 c = √𝟐𝟓𝟎 Figure 6 Here, a = 27, b = ?, c = 45 By Baudhāyana-Pythagoras Theorem c2 = a2 + b2 452 = 272 + b2 2025 = 729+ b2 2025 – 729 = b2 1296 = b2 b2 = 1296 b = √1296 b = 𝟑𝟔

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