Question 1 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)

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[Ganita Prakash] Find the diagonal of a square with sidelength 5 cm - Figure it out - Page 52, 53, 54

part 2 - Question 1 - Figure it out - Page 52, 53, 54 - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2) - Class 8 (Ganita Prakash - 1, 2 & Old NCERT)

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Question 1 Find the diagonal of a square with sidelength 5 cm.Here, Diagonal is BD From Pythagoras Theorem Hypotenuse2 = Base2 + Height2 BD2 = AB2 + AD2 BD2 = 52 + 52 BD2 = 25 + 25 BD2 = 50 BD = โˆš๐Ÿ“๐ŸŽ BD = โˆš(2 ร— 25) BD = โˆš(2 ร— 5^2 ) BD = โˆš2 ร— โˆš(5^2 ) BD = โˆš2 ร— 5 BD = ๐Ÿ“โˆš๐Ÿ Thus, Diagonal is of length โˆš๐Ÿ“๐ŸŽ cm or ๐Ÿ“โˆš๐Ÿ cm

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