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Question 1 - Figure it out (Page 47) - Baudhāyana’s Theorem on Right-angled triangles - Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
Last updated at February 20, 2026 by Teachoo
Class 8 (Ganita Prakash - 1, 2 & Old NCERT)
Chapter 2 Class 8 - The Baudhayana-Pythagoras Theorem (Ganita Part 2)
- Doubling a square
- Halving a square
- Hypotenuse of an Isosceles Right Triangle
- Decimal Representation of √2
- Figure it out - Page 39, 40
- Formula for Hypotenuse of an Isosceles Right Triangle
- Combining Two squares
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Baudhāyana’s Theorem on Right-angled triangles
- Pythagorean triples
- Figure it out - Page 50
- A Long-Standing Open Problem
- Further Applications of the Baudhāyana - Pythagoras Theorem
- Figure it out - Page 52, 53, 54
Transcript
Question 1 - Figure it out (Page 47) If a right-angled triangle has shorter sides of lengths 5 cm and 12 cm, then what is the length of its hypotenuse? First draw the right-angled triangle with these sidelengths and measure the hypotenuse, then check your answer using Baudhāyana’s Theorem. Let’s draw a diagram Now, by Baudhāyana-Pythagoras Theorem c2 = a2 + b2 c2 = 52 + 122 c2 = 25 + 144 c2 = 169 c = √169 c = √(13^2 ) c = 13 Thus, Hypotenuse is 13 cm Note: Since length is given in cm, we have to write 13 cm and not 13
