Ex 11.1, 15 - Does point (-2.5, 3.5) lie inside, outside or on - Circle

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise

Transcript

Ex 11.1, 15 (Introduction) Does the point ( 2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25? We know that equation of circle is (x h)2 + (y k)2 = r2 where (h, k) is the centre & r is the radius of circle If for any point (a, b) (i) (a h) 2 + (b k) 2 = r2 Then point (a, b) lies on the circle (ii) (a h) 2 + (b k) 2 < r2 Then point (a, b) lie inside the circle (iii) (a h) 2 + (b k) 2 > r2 Then point (a, b) lie outside the circle Ex 11.1, 15 (Method 1) Does the point ( 2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25? Given equation x2 + y2 = 25 (x 0)2 + (y 0)2 = 52 We know that equation of circle is (x h)2 + (y k)2 = r2 Here, h = 0, k = 0 & r = 5 Hence centre = (h, k) = (0, 0) radius = r = 5 Finding distance between centre (0, 0) & point ( 2.5, 3.5) We know that distance between two point (x1, y1) & (x2, y2) is d = 2 1 2+ 2 1 2 Putting values = 0 2.5 2+ 0 3.5 2 = 2.5 2+ 3.5 2 = 6.25+12.25 = 18.50 < 25 < 5 Thus, distance between centre (0,0) & point (-2.5, 3.5) is 18.50 which is less than 5 (radius) Hence point (-2.5, 3.5) lies inside the circle Ex 11.1, 15 (Method 2) Does the point ( 2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25? We know that equation of circle is (x h)2 + (y k)2 = r2 where (h, k) is the centre & r is the radius of circle If for any point (a, b) (i) (a h) 2 + (b k) 2 = r2 Then point (a, b) lies on the circle (ii) (a h) 2 + (b k) 2 < r2 Then point (a, b) lie inside the circle (iii) (a h) 2 + (b k) 2 > r2 Then point (a, b) lie outside the circle Given that Equation of circle is x2 + y2 = 25 We need to find that Point ( 2.5, 3.5) lie inside, outside or on the circle x2 + y2 = 25 Putting x = 2.5 & y = 3.5 in x2 + y2 = ( 2.5)2 + (3.5)2 = 6.25 + 12.25 = 18.50 < 25 Thus, ( 2.5)2 + (3.5)2 < 25 i.e. (a h) 2 + (b k) 2 < r2 Point ( 2.5, 3.5) lie inside the circle x2 + y2 =25

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.