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Ex 11.1, 2 - Equation of circle with centre (-2, 3) radius 4 - Circle

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise
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Ex 11.1, 2 Find the equation of the circle with centre (–2, 3) and radius 4 We know that equation of a circle is (x­ – h)2 + (y ­– k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = (–2, 3) So h = −2 & k = 3 & radius (r) = 4. Putting values in (1) (x − (−2))2 + (y – 3)2 = (4)2 (x + 2)2 + (y – 3)2 = 16 (x2 + 22 + 4x) + (y2 + 32 − 6y) = 16 x2 + 4 + 4x + y2 + 9 – 6y = 16 x2 + y2 + 4x – 6y + 4 + 9 = 16 x2 + y2 + 4x – 6y + 13 − 16 = 0 x2 + y2 + 4x – 6y − 3 = 0

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