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Ex 11.1, 9 - Find centre, radius of circle 2x2 + 2y2 - x = 0

Ex 11.1,  9 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.1,  9 - Chapter 11 Class 11 Conic Sections - Part 3

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Transcript

Ex 10.1, 9 Find the centre and radius of the circle 2x2 + 2y2 – x = 0 Given 2x2 + 2y2 – x = 0 We need to make this in form (x – h)2 + (y – k)2 = r2 From (1) 2x2 + 2y2 – x = 0 2("x2 + y2" − 𝑥/2) = 0 x2 + y2 − 𝑥/2 = 0/2 x2 − 𝑥/2 + y2 = 0 Ex 10.1, 9 Find the centre and radius of the circle 2x2 + 2y2 – x = 0 Given 2x2 + 2y2 – x = 0 We need to make this in form (x – h)2 + (y – k)2 = r2 From (1) 2x2 + 2y2 – x = 0 2("x2 + y2" − 𝑥/2) = 0 x2 + y2 − 𝑥/2 = 0/2 x2 − 𝑥/2 + y2 = 0 (x)2 − 2 × (1/4)(x) + y2 = 0 [x2 − 2 × (1/4)x + (1/4)^2] − (1/4)^2 + y2 = 0 [x2 − 2 × (1/4)x + (1/4)^2] − (1/4)^2 + y2 = 0 Using (a − b)2 = a2 + b2 − 2ab (𝑥−1/4)"2 − " (1/4)^2 " + y2 = 0" (𝑥−1/4)2 + y2 = (1/4)^2 (𝑥−1/4)2 + (y − 0)2 = (1/4)^2 Comparing (2) with (x – h)2 + (y – k)2 = r2 h = 1/4 , k = 0 & r = 1/4 Hence, Center of circle (𝟏/𝟒 ", 0" ) and Radius of circle = r = 𝟏/𝟒

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.