Ex 11.1, 4 - Equation of circle centre (1, 1) radius root2 - Ex 11.1

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise
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Ex 11.1, 4 Find the equation of the circle with centre (1, 1) and radius ﷐﷮2﷯ We know that equation of a circle is (x­ – h)2 + (y ­– k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = (1, 1) So h = 1 & k = 1 & radius (r) = ﷐﷮2﷯. Putting values in (1) (x – 1)2 + (y – 1)2 = (﷐﷮2﷯)2 x2 + 12 − 2x + y2 + 12 − 2y = 2 x2 + y2 – 2x – 2y + 2 = 0

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