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Ex 11.1, 4 Find the equation of the circle with centre (1, 1) and radius √2 We know that equation of a circle is (x­ – h)2 + (y ­– k)2 = r2 Where (h, k) is the centre & r is the radius Here Centre (h, k) = (1, 1) So h = 1 & k = 1 & radius (r) = √2. Putting values in (1) (x – 1)2 + (y – 1)2 = (√2)2 x2 + 12 − 2x + y2 + 12 − 2y = 2 x2 + y2 – 2x – 2y = 0

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.