Question 29 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards

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Question 29 (A) On a particular day, 50000 people attended a Cricket Test Match between India and Australia in Sydney Cricket Ground. Let x be the number of adults attended the cricket match and y be the number of children attended the cricket match. Cost of an adult ticket was ₹1000 while cost of a child ticket was ₹200. On that day Revenue earned by selling all 50,000 tickets, was ₹4,20,00,000. Find how many adults and how many children attended the cricket match?Given Number of adults attending cricket match = x Number of children attending cricket match = y Now, Total 50,000 people attended the match. So, we can write Number of adults + Number of children = 50,000 x + y = 50,000 Also, Cost of an adult ticket was ₹1000 while cost of a child ticket was ₹200. And, total revenue ₹4,20,00,000 Now, Revenue earned by selling 1 adult ticket = ₹ 1,000 Revenue earned by selling x adult tickets = ₹ 1,000 × x And, Revenue earned by selling 1 child ticket = ₹ 200 Revenue earned by selling y child tickets = ₹ 200 × y Also, total revenue ₹4,20,00,000. So, we can write Revenue from adults + Revenue from children = ₹4,20,00,000 ₹ 1,000 × x + ₹ 200 × y = ₹4,20,00,000 1000x + 200y = 4,20,00,000 Dividing by 200 both sides 1,000𝑥/200+200𝑦/200=4,20,00,000/200 5x + y = 2,10,000 Now, our equations are x + y = 50,000 …(1) 5x + y = 2,10,000 …(2) Doing (2) – (1) (5x + y) – (x + y) = 2,10,000 – 50,000 5x – x + y – y = 1,60,000 4x = 1,60,000 x = 1,60,000/4 x = 40,000 Putting value of x in (1) x + y = 50,000 40,000 + y = 50,000 y = 50,000 – 40,000 y = 10,000 Therefore, Number of adults attended the match is 40,000 and number of children attended is 10,000