Find the smallest number which is divisible by both 306 and 657. - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 21 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 21 (B) Find the smallest number which is divisible by both 306 and 657.Smallest number divisible by both 306 and 657 is their LCM Note: You can take numbers like 2 & 5 and check. So, smallest number divisible by 2 & 5 is 10. Which is their LCM. (HCF of 2 & 5 is 1) Finding LCM of 306 & 657 Thus, L.C.M = 2 × 3 × 3 × 17 × 73 = 22338 Thus, required number is 22338

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