If sin 𝒙 = 7/25 , where π‘₯ is an acute angle, then find the value of - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 25 (B) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

Remove Ads

Transcript

Question 25 (B) If sin 𝒙 = 7/25 , where π‘₯ is an acute angle, then find the value of sin𝒙. cos𝒙(tan𝒙 + cot𝒙).Now, we need to find 𝐬𝐒𝐧⁑𝒙 πœπ¨π¬β‘π’™ (π­πšπ§β‘π’™+πœπ¨π­β‘π’™ ) Putting tan x and cot x in terms of sin and cos Our equation becomes 𝐬𝐒𝐧⁑𝒙 πœπ¨π¬β‘π’™ (π­πšπ§β‘π’™+πœπ¨π­β‘π’™ ) =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ ((𝑠𝑖𝑛 π‘₯)/(π‘π‘œπ‘  π‘₯)+(π‘π‘œπ‘  π‘₯)/(𝑠𝑖𝑛 π‘₯)) =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ ((𝑠𝑖𝑛 π‘₯ Γ—sin⁑π‘₯ + cos⁑π‘₯ Γ—cos⁑π‘₯ )/(sin⁑π‘₯ Γ— π‘π‘œπ‘  π‘₯)) =π’”π’Šπ’β‘π’™ 𝒄𝒐𝒔⁑𝒙 ((〖𝐬𝐒𝐧〗^πŸβ‘π’™ + γ€–πœπ¨π¬γ€—^πŸβ‘π’™)/(π’”π’Šπ’β‘π’™ Γ— 𝒄𝒐𝒔 𝒙)) Putting sin^2⁑π‘₯ + cos^2⁑π‘₯=1 =𝑠𝑖𝑛⁑π‘₯ π‘π‘œπ‘ β‘π‘₯ (1/(sin⁑π‘₯ Γ— π‘π‘œπ‘  π‘₯)) =𝟏 Thus, answer is 1

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.