The circumferences of two circles are in the ratio 3 : 4. The ratio of - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 17 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10
part 3 - Question 17 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 17 The circumferences of two circles are in the ratio 3 : 4. The ratio of their areas is (A) 3 : 4 (B) 4 : 3 (C) 9 : 16 (D) 16 : 9Let the radius of two circles be r1 and r2 Given ratio of their circumferences is 3 : 4 So, (πΆπ‘–π‘Ÿπ‘π‘’π‘šπ‘“π‘’π‘Ÿπ‘’π‘›π‘π‘’ π‘œπ‘“ 1^𝑠𝑑 π‘π‘–π‘Ÿπ‘π‘™π‘’)/(πΆπ‘–π‘Ÿπ‘π‘’π‘šπ‘“π‘’π‘Ÿπ‘’π‘›π‘π‘’ π‘œπ‘“ 2^𝑛𝑑 π‘π‘–π‘Ÿπ‘π‘™π‘’)=3/4 (2πœ‹π‘Ÿ_1)/(2πœ‹π‘Ÿ_2 )=3/4 𝒓_𝟏/𝒓_𝟐 =πŸ‘/πŸ’ Now, we need to find ratio of their areas So, Ratio of their areas = (π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ 1^𝑠𝑑 π‘π‘–π‘Ÿπ‘π‘™π‘’)/(π΄π‘Ÿπ‘’π‘Ž π‘œπ‘“ 2^𝑛𝑑 π‘π‘–π‘Ÿπ‘π‘™π‘’) = (πœ‹(π‘Ÿ_1 )^2)/(πœ‹(π‘Ÿ_2 )^2 ) = (π‘Ÿ_1 )^2/(π‘Ÿ_2 )^2 =(𝒓_𝟏/𝒓_𝟐 )^𝟐 Putting value from (1) =(3/4)^2 =πŸ—/πŸπŸ” Thus, required ratio is 9 : 16 So, correct answer is (c)

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