Question 16 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards

Last updated at July 27, 2026 by Teachoo

In the given figure, PA is a tangent from an external point P to - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic

part 2 - Question 16 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Question 16 In the given figure, PA is a tangent from an external point P to a circle with centre O and diameter AB. If ∠POB = 115°, then measure of ∠APO is (A) 25° (B) 30° (C) 20° (D) 65°Since AB is a straight line By linear pair ∠ AOP + ∠ POB = 180° ∠ AOP + 115° = 180° ∠ AOP = 180° – 115° ∠ AOP = 65° Also, we know that Tangent is perpendicular to the radius, ∴ OA ⊥ AP So, ∠ PAO = 90° Now, in ∆ APO By angle sum property ∠ AOP + ∠ PAO + ∠ APO = 180° Putting values 65° + 90° + ∠ APO = 180° 155° + ∠ APO = 180° ∠ APO = 180° – 155° ∠ APO = 25° So, correct answer is (a)

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