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Question 25 (A) Evaluate: 2 sin 30° tan 60° − 3 cos2 60° sec2 30°We know that, sin 30° = 1/2 tan 60° =√3 cos 60° = 1/2 sec 30° = 1/cos⁡〖30° 〗 =1/(√3/2)=2/√3 Putting all values 2 sin 30° tan 60° − 3 cos2 60° sec2 30° = 𝟐 ×𝟏/𝟐×√𝟑−𝟑 × (𝟏/𝟐)^𝟐×(𝟐/√𝟑)^𝟐 = √3−3 ×1/4×4/3 = √𝟑−𝟏

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 15 years. He provides courses for Maths, Science and Computer Science at Teachoo