This question is similar to Chapter 8 Class 10 Introduction to Trignometry - Ex 8.2

Please check the question here

https://www.teachoo.com/13225/530/Ex-8.2--1-ii/category/Ex-8.2/

 

Evaluate: 2 sin 30° tan 60° − 3 cos2 60 ° sec2 30° - Teachoo Class 10 - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic part 2 - Question 25 (A) - CBSE Class 10 Sample Paper for 2026 Boards - Maths Basic - Solutions of Sample Papers for Class 10 Boards - Class 10

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Transcript

Question 25 (A) Evaluate: 2 sin 30° tan 60° − 3 cos2 60° sec2 30°We know that, sin 30° = 1/2 tan 60° =√3 cos 60° = 1/2 sec 30° = 1/cos⁡〖30° 〗 =1/(√3/2)=2/√3 Putting all values 2 sin 30° tan 60° − 3 cos2 60° sec2 30° = 𝟐 ×𝟏/𝟐×√𝟑−𝟑 × (𝟏/𝟐)^𝟐×(𝟐/√𝟑)^𝟐 = √3−3 ×1/4×4/3 = √𝟑−𝟏

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