Example 18
Last updated at Dec. 12, 2016 by Teachoo
Transcript
Example 18 If A.M. and G.M. of two positive numbers a and b are 10 and 8, respectively, find the numbers. Now we have a + b = 20 โฆ(1) ab = 64 โฆ(2) From (2) ab = 64 a = 64/๐ Putting a = 64/๐ in (1) a + b = 20 64/๐ + b = 20 (64 + ๐2)/๐ = 20 64 + b2 = 20b b2 โ 20b + 64 = 0 b(b โ 16) โ 4(b โ 16) = 0 (b โ 4)(b โ 16) = 0 b โ 4 = 0 or b โ 16 = 0 b = 4 or b = 16 Hence the numbers are a = 4, b = 16 or b = 4, a = 16
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.