Example 18 - If AM and GM of a, b are 10, 8 - Chapter 9 - AM and GM (Arithmetic Mean And Geometric mean)

Example 18 - Chapter 9 Class 11 Sequences and Series - Part 2
Example 18 - Chapter 9 Class 11 Sequences and Series - Part 3

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Transcript

Example 13 If A.M. and G.M. of two positive numbers a and b are 10 and 8, respectively, find the numbers. Now we have a + b = 20 (1) ab = 64 (2) From (2) ab = 64 a = 64/ Putting a = 64/ in (1) a + b = 20 64/ + b = 20 (64 + 2)/ = 20 64 + b2 = 20b b2 20b + 64 = 0 b(b 16) 4(b 16) = 0 (b 4)(b 16) = 0 b 4 = 0 or b 16 = 0 b = 4 or b = 16 Hence the numbers are a = 4, b = 16 or b = 4, a = 16

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.