Example 18 - Class 11
Last updated at Dec. 12, 2016 by Teachoo
Transcript
Example 18 If A.M. and G.M. of two positive numbers a and b are 10 and 8, respectively, find the numbers. Now we have a + b = 20 …(1) ab = 64 …(2) From (2) ab = 64 a = 64/𝑏 Putting a = 64/𝑏 in (1) a + b = 20 64/𝑏 + b = 20 (64 + 𝑏2)/𝑏 = 20 64 + b2 = 20b b2 – 20b + 64 = 0 b(b – 16) – 4(b – 16) = 0 (b – 4)(b – 16) = 0 b – 4 = 0 or b – 16 = 0 b = 4 or b = 16 Hence the numbers are a = 4, b = 16 or b = 4, a = 16
Examples
Example 1
Example 2
Example 3
Example 4
Example 5
Example 6 Important
Example 7
Example 8
Example 9
Example 10
Example 11
Example 12
Example 13
Example 14 Important
Example 15 Important
Example 16
Example 17 Important
Example 18 Important You are here
Example 19 Important
Example 20
Example 21 Important
Example 22
Example 23 Important
Example 24 Important
Chapter 9 Class 11 Sequences and Series
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
