Example 8 - Class 11
Last updated at May 29, 2018 by Teachoo
Transcript
Example 8 Insert 6 number between 3 and 24 such that the resulting sequence is an AP We know that to insert n number between a and b common difference = d = (๐ โ ๐)/(๐ + 1) Here, We need to insert 6 numbers between 3 and 24 So, b = 24 , a = 3 & number of terms to be inserted = n = 6 Therefore, d = (24 โ 3 )/(6 + 1) = 21/7 = 3 a = 3, d = 3 & b = 24 Hence six numbers between 3 and 24 are 6, 9, 12, 15, 13 & 21.
Examples
Example 1
Example 2
Example 3
Example 4
Example 5
Example 6 Important
Example 7
Example 8 You are here
Example 9
Example 10
Example 11
Example 12
Example 13
Example 14 Important
Example 15 Important
Example 16
Example 17 Important
Example 18 Important
Example 19 Important
Example 20
Example 21 Important
Example 22
Example 23 Important
Example 24 Important
Chapter 9 Class 11 Sequences and Series
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.