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Question (e) - Figure it out - Page 58 - Chapter 3 Class 7 - A peek beyond the Point (Ganita Prakash)
Last updated at June 9, 2025 by Teachoo
Class 7 (Ganita Prakash & Old NCERT)
Chapter 3 Class 7 - A peek beyond the Point (Ganita Prakash)
- Fractions - Quick Revision
- Need for a smaller unit
- Tenth
- Hundredth
-
Figure it out - Page 58
- Decimals
- Fractions to Decimals
- Reading and Writing Decimals
- Unit Conversion - Weight, Length, Money
- Decimal in number line
- Finding greater decimal
- Closest decimal
- Addition and Subtraction of Decimals
- Decimal Sequences
- Estimating Sums and Differences
- More on Decimal System
- Figure it out - Page 78, 79, 80
- Teachoo Questions - MCQs
- Teachoo Questions - Mix
- Teachoo Questions - Assertion Reasoning
- Teachoo Questions - Case Based
Transcript
Question (e) Find the sums and differences: (e) 8 6/100−5 3/100These are mixed fractions, converting them into normal fractions 8 6/100=(8 × 100 + 6)/100=𝟖𝟎𝟔/𝟏𝟎𝟎 5 3/100=(5 × 100 + 3)/100=𝟓𝟎𝟑/𝟏𝟎𝟎 Now, finding difference 𝟖𝟎𝟔/𝟏𝟎𝟎− 𝟓𝟎𝟑/𝟏𝟎𝟎 Since denominator is same, we subtract numerator 𝟖𝟎𝟔/𝟏𝟎𝟎− 𝟓𝟎𝟑/𝟏𝟎𝟎 =(806 − 503)/100 (Note: It is not 86/100 but 806/100) (Note: It is not 53/100 but 503/100) =𝟑𝟎𝟑/𝟏𝟎𝟎 =(300 + 3)/100 =300/100+3/100 =3+3/100 =𝟑 𝟑/𝟏𝟎𝟎
