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Ex 4.1, 24 - Prove (2n + 7) < (n + 3)2 - Chapter 4 Induction - Ex 4.1

Ex 4.1, 24 - Chapter 4 Class 11 Mathematical Induction - Part 2
Ex 4.1, 24 - Chapter 4 Class 11 Mathematical Induction - Part 3
Ex 4.1, 24 - Chapter 4 Class 11 Mathematical Induction - Part 4

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Ex 4.1,24 Prove the following by using the principle of mathematical induction for all n, n is a natural number (2n +7) < (n + 3)2 Introduction Since 1 < 100 then 1 < 100 + 5 i.e. 1 < 105 We will use this theory in our question Ex 4.1,24 Prove the following by using the principle of mathematical induction for all n, n is a natural number (2n +7) < (n + 3)2 Let P(n): (2n +7) < (n + 3)2 For n = 1 L.H.S = (2.1 + 7) = 2 + 7 = 9 R.H.S = (1 + 3)2 = 16 Since 9 < 16 L.H.S < R.H.S P(n) is true for n = 1 Assume P(k) is true (2k + 7) < (k + 3)2 We will prove that P(k + 1) is true. R.H.S = ((k+1) + 3)2 L.H.S = (2(k+1) + 7) L.H.S < R.H.S P(k + 1) is true whenever P(k) is true. By the principle of mathematical induction, P(n) is true for n, where n is a natural number

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.