Example 8 - Find value of sin 31pi/3 - Chapter 3 Class 11 - Examples

part 2 - Example 8 - Examples - Serial order wise - Chapter 3 Class 11 Trigonometric Functions

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Transcript

Example 8 Find the value of sin (31" " π" " )/3 sin 𝟑𝟏𝝅" " /𝟑 = sin (10π + 𝟏/𝟑 "π ") = sin (5 × (2π) + 1/3 "π ") = sin (𝟏/𝟑 " π" ) = sin (1/3 " × 180°" ) = sin 60° = √𝟑/𝟐

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