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1. Chapter 3 Class 11 Trigonometric Functions
2. Concept wise
3. Finding Value of trignometric functions, given angle

Transcript

Ex 3.3, 8 Prove that cosβ‘γ (Ο + π₯) cosβ‘γ(β π₯)γ γ/(sinβ‘γ (Ο β π₯)γ cosβ‘γ"(" Ο/2 " + " π₯")" γ ) = cot2 π₯ Taking L.H.S. πππ β‘γ(π + π₯) γπππ  γβ‘γ(βπ₯)γ γ/(π ππβ‘(π β π₯) πππ β‘γ"(" π/2 " + " π₯")" γ ) Putting Ο = 180Β° = πππ β‘γ(180Β° + π₯) γπππ  γβ‘γ(βπ₯)γ γ/(π ππβ‘(180Β° β π₯) πππ β‘γ"(" 90Β° "+ " π₯")" γ ) Using cos (180Β° + x) = βcos x cos (βx) = cos x sin (180Β° β x) = sin x & cos(90Β° + x) = βsin x = (βπππ β‘γπ₯ Γ πππ β‘π₯ γ)/((sinβ‘γπ₯) Γγ(βsinγβ‘π₯) γ ) = (βπππ 2π₯)/(βπ ππ2π₯) = cot2x = R.H.S. Hence proved

Finding Value of trignometric functions, given angle

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.