For general solutions
We must learn
For sin x = sin y,
x = nπ + (–1) n y, where n ∈ Z
For cos x = cos y ,
x = 2nπ ± y, where n ∈ Z
For tan x = tan y,
x = nπ + y, where n ∈ Z
Note : Here n ∈ Z means n is an integer
![Finding general solutions - Part 2](https://d1avenlh0i1xmr.cloudfront.net/655ea19e-ec7d-4e16-9188-aa9477ece21c/slide2.jpg)
![Finding general solutions - Part 3](https://d1avenlh0i1xmr.cloudfront.net/d883859b-c0fc-4bfe-81ac-19f849f6446f/slide3.jpg)
![Finding general solutions - Part 4](https://d1avenlh0i1xmr.cloudfront.net/63707913-2316-4a23-92d5-b6f821d166ea/slide4.jpg)
![Finding general solutions - Part 5](https://d1avenlh0i1xmr.cloudfront.net/49f08d52-03a3-4eaa-be7d-42ff6bd04acd/slide5.jpg)
![Finding general solutions - Part 6](https://d1avenlh0i1xmr.cloudfront.net/1f096855-2c92-4964-a2f8-62db05aec525/slide6.jpg)
Finding General Solutions
Finding General Solutions
Last updated at April 16, 2024 by Teachoo
For general solutions
We must learn
For sin x = sin y,
x = nπ + (–1) n y, where n ∈ Z
For cos x = cos y ,
x = 2nπ ± y, where n ∈ Z
For tan x = tan y,
x = nπ + y, where n ∈ Z
Note : Here n ∈ Z means n is an integer
For general solutions We must learn For sin x = sin y, x = nπ + (–1)n y, where n ∈ Z For cos x = cos y, x = 2nπ ± y, where n ∈ Z For tan x = tan y, x = nπ + y, where n ∈ Z Note: Here n ∈ Z means n is an integer