Question 3 - Finding General Solutions - Chapter 3 Class 11 Trigonometric Functions

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Example 20 - Find solution of sin x = - root 3/2 - Class 11 - Examples

Example 20 - Chapter 3 Class 11 Trigonometric Functions - Part 2

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Question 3 Find the solution of sin x = – √3/2 Let sin x = sin y also sin x = (−√3)/2 From (1) and (2) sin y = (−√3)/2 sin y = sin 4/3 π ⇒ y = 4/3 π Step 2 Since sin x = sin y General Solution is x = n π + (–1)n y where n ∈ Z Putting y = 4𝜋/3 x = n π + (–1)n 4/3 π where n ∈ Z

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.