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Last updated at Feb. 12, 2020 by Teachoo

Transcript

Ex 3.3, 3 Prove that cot2 π/6 + cosec 5π/6 + 3 tan2 π/6 = 6 Taking L.H.S. cot2 π/6 + cosec 5π/6 + 3 tan2 π/6 Putting π = 180° = cot2(180/6) + cosec((5 ×180)/6) + 3 tan2(180/6) = cot2 30° + cosec (150°) + 3tan2 30° Here, tan 30° = 1/√3 cot 30° = 1/tan〖30°〗 = 1/(1/√3) = √3 For cosec 150° , First, Finding sin 150° sin 150° = sin (180 – 30° ) = sin 30° = 1/2 cosec 150° = 1/sin〖150°〗 = 1/(1/2) = 2 Putting values = cot2 30° + cosec (150°) + 3tan2 30° = (√3)2 + 2 + 3 × (1/√3)^2 = 3 + 2 + 3 × 1/3 = 3 + 2 + 1 = 6 = R.H.S Hence proved

Finding Value of trignometric functions, given angle

Negative Angle Identities

Value of sin, cos, tan repeats after 2π

Shifting angle by π/2, π, 3π/2 , 2π

Example 8

Ex 3.2, 9 Important

Ex 3.2, 8 Important

Ex 3.2, 10 Important

Example 9 Important

Ex 3.2, 6

Ex 3.2, 7 Important

Example 10

Ex 3.3, 1

Ex 3.3, 2 Important

Ex 3.3, 3 Important You are here

Ex 3.3, 4

Ex 3.3, 8 Important

Ex 3.3, 9 Important

Find values of sin 18, cos 18, cos 36, sin 36, sin 54, cos 54 Important

Chapter 3 Class 11 Trigonometric Functions

Concept wise

- Radian measure - Conversion
- Arc length
- Finding Value of trignometric functions, given other functions
- Finding Value of trignometric functions, given angle
- (x + y) formula
- 2x 3x formula - Proving
- 2x 3x formula - Finding value
- cos x + cos y formula
- 2 sin x sin y formula
- Finding Principal solutions
- Finding General Solutions
- Sine and Cosine Formula

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.