Practice Questions CBSE - Science Class 10 (2023 Boards)

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Question 17 [Assertion Reasoning] Important

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Question 21 (Choice 1) Important

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Question 30 Important You are here

Question 31 (a)

Question 31 (b) Important

Question 32 (Choice 1)

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Question 33 (a)

Question 33 (b)

Question 33 (c) Important

Question 34 (a) - Choice 1

Question 34 (b) - Choice 1 Important

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Question 37 (a) - Choice 1 [Case Based]

Question 37 (b) i - Choice 2 [Case Based] Important

Question 37 (b) ii - Choice 2 [Case Based] Important

Question 38 (a) - Choice 1 [Case Based]

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Question 39 (b) - Choice 1 [Case Based]

Question 39 (c) - Choice 1 [Case Based]

Question 39 (d) - Choice 1 [Case Based] Important

Question 39 (d) - Choice 2 [Case Based] Important

An object of height h is kept at point P in front of a mirror as shown below. The height of the image produced is h'. In the diagram, F is the focus and C is the centre of curvature. 

An object of height - Teachoo.jpg

(a) If the object is now moved to point C, will the height of the image now produced be less than, equal to, or greater than h'? Give a reason for your answer. 

(b) If the focal length of the mirror is 20 cm and the distance between points P and C is 10 cm, determine the distance between the images produced when the object is kept at P and C.

 

Answer.

(a) M = H’/H

  • Image produced in the given case (object between C and F) is greater than the object in size

concave-mirror---object-at-infinity---ray-diagaram---teachoo.jpg

Therefore, M>1.

  • When object is at C, image is also produced at C.

H’=H

concave-mirror---object-at-infinity---ray-diagaram---teachoo.jpg

Therefore, M=1.

Thus the height of the image produced when the object is at C will be less than the image produced when object is between C and F.

(b)

To find the distance between the two images we need to find the image distance when the object is at P and when it is at C.

  • To find the image distance when the object is at P

u = -30 cm 

f = -20 cm 

  • Using mirror formula :
    1/f=1/u+1/v 
  • v1 = -60 cm
  • To find the image distance when the object is at C :
    Since C is the centre of curvature,
    image distance = object distance (i.e.) 
  • v2 = - 40 cm

Distance between the images = |v2| - |v1| = 60 - 40 = 20 cm 

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CA Maninder Singh is a Chartered Accountant for the past 13 years and a teacher from the past 17 years. He teaches Science, Economics, Accounting and English at Teachoo