Last updated at Feb. 25, 2017 by Teachoo

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Example 6 A juice seller was serving his customers using glasses as shown in figure. The inner diameter of the cylindrical glass was 5 cm, but the bottom of the glass had a hemispherical raised portion which reduced the capacity of the glass. If the height of a glass was 10 cm, find the apparent capacity of the glass and its actual capacity. (Use = 3.14.) Apparent capacity of the glass = Volume of cylinder Actual capacity of the glass = Volume of cylinder volume of hemisphere Volume of cylinder Given inner diameter of the glass = 5 cm So, radius = r = /2 "=" 5/2 = 2.5 cm Height = 10 cm Volume of the cylindrical glass = 2 = 3.14 (2.5)2 10 = 3.14 2.5 2.5 10 = 3.14 6.25 10 = 196.25 cm3 Volume of the hemisphere Radius of hemisphere = r = 2.5 cm Volume of the hemisphere = 2/3 r3 = 2/3 3.14 (2.5)3 = 2/3 3.14 2.5 2.5 2.5 = 2/3 3.14 15.62 = 32.7 cm3 Now, Apparent capacity of the glass = Volume of cylinder = 196.25 cm3 Actual capacity of the glass = Total volume of cylinder volume of hemisphere = 196.25 32.7 = 163.54cm3 Hence, apparent capacity = 196.25cm3 Actual capacity of the glass = 163.54cm3

Example 2
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Example 3 Important

Ex 13.1, 4 Important

Ex 13.1, 9 Important

Example 6 Important You are here

Example 7 Important

Example 9 Important

Example 11 Important

Ex 13.3, 8 Important

Ex 13.3, 9 Important

Example 12 Important

Ex 13.4, 4 Important

Ex 13.4, 5 Important

Surface Area and Volume Formulas Important

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.