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Example 6 - Savita and Hamida are friends. What is probability - Others

  1. Class 10
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Example 6 Savita and Hamida are friends. What is the probability that both will have different birthdays? (ignoring a leap year). P(both have different birthday) = P(both will not have same birthday) = 1 โ€“ P(both will have same birthday) = 1 โ€“ 1/365 = (365 โˆ’ 1)/365 = 364/365 Example 6 Savita and Hamida are friends. What is the probability that both will have (ii) same birthday? (ignoring a leap year). Number of days in an year = 365 Number of days when same birthday is possible = 1 P(both have same birthday) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘Ž๐‘ฆ๐‘  ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐‘กโ„Ž๐‘’๐‘ฆ ๐‘๐‘Ž๐‘› โ„Ž๐‘Ž๐‘ฃ๐‘’ ๐‘ ๐‘Ž๐‘š๐‘’ ๐‘๐‘–๐‘Ÿ๐‘กโ„Ž๐‘‘๐‘Ž๐‘ฆ ๐‘–๐‘› ๐‘Ž๐‘› ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘‘๐‘Ž๐‘ฆ๐‘  ๐‘–๐‘› ๐‘Ž๐‘› ๐‘ฆ๐‘’๐‘Ž๐‘Ÿ) = 1/365

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
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