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Example 6 - Chapter 15 Class 10 Probability (Important Question)

Last updated at May 29, 2023 by

Example 6 - Savita and Hamida are friends. What is probability - Others

Example 6 - Chapter 15 Class 10 Probability - Part 2

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Example 6 Savita and Hamida are friends. What is the probability that both will have different birthdays? (ignoring a leap year). P(both have different birthday) = P(both will not have same birthday) = 1 – P(both will have same birthday) = 1 – 1/365 = (365 − 1)/365 = 364/365 Example 6 Savita and Hamida are friends. What is the probability that both will have (ii) same birthday? (ignoring a leap year). Number of days in an year = 365 Number of days when same birthday is possible = 1 P(both have same birthday) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠 𝑤ℎ𝑒𝑟𝑒 𝑡ℎ𝑒𝑦 𝑐𝑎𝑛 ℎ𝑎𝑣𝑒 𝑠𝑎𝑚𝑒 𝑏𝑖𝑟𝑡ℎ𝑑𝑎𝑦 𝑖𝑛 𝑎𝑛 𝑦𝑒𝑎𝑟)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠 𝑖𝑛 𝑎𝑛 𝑦𝑒𝑎𝑟) = 1/365

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