Last updated at May 29, 2018 by Teachoo

Transcript

Example 6 Savita and Hamida are friends. What is the probability that both will have different birthdays? (ignoring a leap year). P(both have different birthday) = P(both will not have same birthday) = 1 – P(both will have same birthday) = 1 – 1/365 = (365 − 1)/365 = 364/365 Example 6 Savita and Hamida are friends. What is the probability that both will have (ii) same birthday? (ignoring a leap year). Number of days in an year = 365 Number of days when same birthday is possible = 1 P(both have same birthday) = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠 𝑤ℎ𝑒𝑟𝑒 𝑡ℎ𝑒𝑦 𝑐𝑎𝑛 ℎ𝑎𝑣𝑒 𝑠𝑎𝑚𝑒 𝑏𝑖𝑟𝑡ℎ𝑑𝑎𝑦 𝑖𝑛 𝑎𝑛 𝑦𝑒𝑎𝑟)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑑𝑎𝑦𝑠 𝑖𝑛 𝑎𝑛 𝑦𝑒𝑎𝑟) = 1/365

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.