Last updated at May 29, 2018 by Teachoo

Transcript

Example 4 (Introduction) A sweet seller has 420 kaju barfis and 130 badam barfis. She wants to stack them in such a way that each stack has the same number, and they take up the least area of the tray. What is the maximum number of barfis that can be placed in each stack for this purpose? Suppose we have to stack 12 kaju barfis & 4 badam barfis Maximum number of barfis to stack = 4 = HCF of 12 & 4 Similarly , we will do in this question Example 4 A sweet seller has 420 kaju barfis and 130 badam barfis. She wants to stack them in such a way that each stack has the same number, and they take up the least area of the tray. What is the maximum number of barfis that can be placed in each stack for this purpose? Maximum number of Barfi’s that can be placed = HCF of 420 and 130 Using Euclid’s Division Algorithm Since 420 > 130 We divide 420 by 130 Since the remainder is not 0, We divide 130 by 30 Since the remainder is not 0, We divide 30 by 10 Since remainder is 0 HCF of 420 & 130 is 10 Therefore, Maximum number of Barfi’s that can be placed = HCF of 420 and 130 = 10

Class 10

Important Questions for Exam - Class 10

- Chapter 1 Class 10 Real Numbers
- Chapter 2 Class 10 Polynomials
- Chapter 3 Class 10 Pair of Linear Equations in Two Variables
- Chapter 4 Class 10 Quadratic Equations
- Chapter 5 Class 10 Arithmetic Progressions
- Chapter 6 Class 10 Triangles
- Chapter 7 Class 10 Coordinate Geometry
- Chapter 8 Class 10 Introduction to Trignometry
- Chapter 9 Class 10 Some Applications of Trignometry
- Chapter 10 Class 10 Circles
- Chapter 11 Class 10 Constructions
- Chapter 12 Class 10 Areas related to Circles
- Chapter 13 Class 10 Surface Areas and Volumes
- Chapter 14 Class 10 Statistics
- Chapter 15 Class 10 Probability

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.