Ex 1.1, 4 - Chapter 1 Class 10 Real Numbers (Important Question)

Last updated at July 28, 2026 by

Ex 1.1, 4 - Given that HCF (306, 657) = 9, find LCM - Ex 1.1 - Ex 1.1

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Ex 1.1, 4 Given that HCF (306, 657) = 9, find LCM (306, 657). We know that H.C.F × L.C.M = Product of numbers 9 × L.C.M = 306 × 657 L.C.M = (306 × 657)/9 L.C.M = 22338 ∴ L.C.M of 306 & 657 is 22338

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