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Ex 1.2, 3  - Find the LCM and HCF of following integers - LCM/HCF

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Ex 1.2, 3 - Chapter 1 Class 10 Real Numbers - Part 2
Ex 1.2, 3 - Chapter 1 Class 10 Real Numbers - Part 3

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Ex 1.2 , 3 (Method 1) Find the LCM and HCF of the following integers by applying the prime factorisation method. 12, 15 and 21 H.C.F = Product of smallest power of each common prime factor = 31 = 3 L.C.M = Product of greatest power of each prime factor = 22 × 3 × 5 × 7 = 4 × 3 × 5 × 7 = 420 Ex 1.2 , 3 (Method 2) Find the LCM and HCF of the following integers by applying the prime factorisation method. 12, 15 and 21 12 = 2 × 2 × 3 15 = 3 × 5 21 = 3 × 7 H.C.F = 3 Finding L.C.M L.C.M = 2 × 2 × 3 × 5 × 7 = 420

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.