Ex 14.1, 19 - Chapter 15 Class 10 Probability (Important Question)

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Ex 14.1, 19 - A child has a die whose six faces shows letters - Ex 15.1

part 2 - Ex 14.1, 19 - Ex 15.1 - Serial order wise - Chapter 14 Class 10 Probability

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Ex 14.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting A? Total number of faces on the die = 6 Number of faces having A on it = 2 P (getting A) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’๐‘  โ„Ž๐‘Ž๐‘ฃ๐‘–๐‘›๐‘” ๐ด)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’๐‘  ๐‘œ๐‘› ๐‘‘๐‘–๐‘’) = 2/6 = ๐Ÿ/๐Ÿ‘ Ex 14.1, 19 A child has a die whose six faces shows the letters as given below: The die is thrown once. What is the probability of getting (ii) D? Total number of faces on the die = 6 Number of faces having D on it = 1 P (getting D) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’๐‘  โ„Ž๐‘Ž๐‘ฃ๐‘–๐‘›๐‘” ๐ท)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘“๐‘Ž๐‘๐‘’๐‘  ๐‘œ๐‘› ๐‘‘๐‘–๐‘’) = ๐Ÿ/๐Ÿ”

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