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Chapter 13 Class 10 Surface Areas and Volumes
Example 3 Important
Ex 13.1, 4 Important You are here
Ex 13.1, 9 Important
Example 6 Important
Example 7 Important
Example 9 Important Deleted for CBSE Board 2023 Exams
Example 11 Important Deleted for CBSE Board 2023 Exams
Ex 13.3, 8 Important Deleted for CBSE Board 2023 Exams
Ex 13.3, 9 Important Deleted for CBSE Board 2023 Exams
Example 12 Important Deleted for CBSE Board 2023 Exams
Ex 13.4, 4 Important Deleted for CBSE Board 2023 Exams
Ex 13.4, 5 Important Deleted for CBSE Board 2023 Exams
Surface Area and Volume Formulas Important
Chapter 13 Class 10 Surface Areas and Volumes
Last updated at May 29, 2018 by Teachoo
Ex 13.1, 4 A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid. The hemisphere can occupy whole of the side of cube. Hence, Greatest diameter of hemisphere = side of cube = 7 cm Here, base of hemisphere falls on cube, so that Area should not from part of solid. Surface area of solid = Area of cube + Curved surface area of hemisphere Base area of hemisphere Area of cube Here, a = side = 7 cm Area of cube = 6a2 = 6 (7)2 = 6 (7 7) = 6 49 = 294 cm2 Curved surface area of hemisphere Diameter of hemisphere = 7 cm Hence, radius = r = (Diameter )/2 = 7/2 cm Curved Surface area of hemisphere = 2 2 = 2 22/7 (7/2)^2 = 2 22/7 7/2 7/2 = 77 cm2 Base area of hemisphere Base of hemisphere is a circle with radius = radius of hemisphere = r = 7/2 Base area of hemisphere = r2 = 22/7 (7/2)^2 = 22/7 7/2 7/2 = 77/2 cm2 Now, Surface area of solid = Area of cube + Curved surface area of hemisphere Base area of hemisphere = 294 + 77 77/2 = 294 + 77 38.5 = 371 38.5 = 332.5 cm2 Hence, Surface area of solid = 332.5 cm2