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Chapter 13 Class 10 Surface Areas and Volumes
Example 3 Important
Ex 13.1, 4 Important
Ex 13.1, 9 Important
Example 6 Important
Example 7 Important
Example 9 Important Deleted for CBSE Board 2023 Exams
Example 11 Important Deleted for CBSE Board 2023 Exams
Ex 13.3, 8 Important Deleted for CBSE Board 2023 Exams You are here
Ex 13.3, 9 Important Deleted for CBSE Board 2023 Exams
Example 12 Important Deleted for CBSE Board 2023 Exams
Ex 13.4, 4 Important Deleted for CBSE Board 2023 Exams
Ex 13.4, 5 Important Deleted for CBSE Board 2023 Exams
Surface Area and Volume Formulas Important
Chapter 13 Class 10 Surface Areas and Volumes
Last updated at May 14, 2021 by Teachoo
Ex 13.3, 8 Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed? Canal is the shape of cuboid where Breadth = 6 m Height = 1.5 m & Speed of canal = 10 km/hr Length of canal in 1 hour = 10 km Length of canal in 60 minutes = 10 km Length of canal in 1 min = 1/60 x 10 km Length of canal in 30 min = 30/60 10 = 5km = 5000 m Now, Volume of canal = Length Breadth Height = 5000 6 1.5 m3 Now Volume of water in canal = Volume of area irrigated Volume of water in canal = Area irrigated Height 5000 6 1.5 m3 = Area irrigated 8 cm 5000 6 1.5 m3 = Area irrigated 8/100 m (5000 6 1.5 100 )/8 = Area irrigated Area irrigated = 562500 m2 Area irrigated = 562500/10000 hectares Area irrigated = 56.25 hectares